Question

Equation of the plane through the mid point of the joint of A(4*5,-10) and B(-1,2,1) and perpendicular toAB is

Answer 1

Answer:

Since, the line AB is perpendicular to the plane, it has to be the normal to the plane.

DR's of normal =(4+1,5−2,−10−1)=(5,3,−11)

Hence, the equation of the plane is of the form,

5x+3y−11z=d

The midpoint of AB is ( 3/2 , 7/2, -9/2)

The plane passes through this point, so the value of d is 135/2

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