Question

Equation of the tangent to the
9x² +4y^2=36 which are
parallel
to y-axis is x=+-k
then k² =​

Answer 1

Answer: Your answer is 0

Step-by-step explanation:

Given hyperbola may be written as,

36

x

2

−

9

y

2

=1

a

2

=36,b

2

=9

Equation of line perpendicular to the line x−y+4=0 is given by,

y=−x+c

Now for this line to be tangent to the given hyperbola, c

2

=a

2

m

2

−b

2

⇒c

2

=36−9=27⇒c=±3

3

Hence required line is, x+y±3

3

=0

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Answer 2

Answer : # 0

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