Question

Equation of trajectory of projectile is y = √3x-0.8x^2. •Initial velocity of projectile object.
a) 25
b)10
c)5
d)5/2
pls help,with step by step solution.​

Answer 1

Explanation:

equation of trajectory

y = x tantheta - ½ a x²/ u²cos²theta

given Y = √3 x - 0.8 x²

½ 10 x²/ u² cos² theta = 0.8 x²

as tan theta = √3

theta =60⁰

thus ,

cos² theta = 1/4

5 / u² = 0.8 /4

5/ u² = 1/5

u² = 25

u = 5m/s