equation of (x+1)square-xsquare=0 has real roots equal to
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the question is invalid since on solving we get to a step where the equation is x+1=x which gives 1=0 which is not true hence the equation is not true
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Answer:
Yes. x= -1/2
Step-by-step explanation:
Given (x+1)² - x² = 0
x²+2x+1 - x² = 0
2x+1 = 0
x= -1/2
This is the only root for given equation.
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