Question

equation P X square + 4 x minus 3 equals to zero has real roots then find the value of p​

Answer 1

Answer:

P$\geq$-$\frac{4}{3}$, P is real number

Step-by-step explanation:

The equation has real roots

So $D/4\geq 0$

P*x^2 + 4x - 3 = 0

D/4 = 2^2 + 3P$\geq 0$

3P$\geq -4$

P$\geq -\frac{4}{3}$

but if P isn't a real number, the roots cannot be real number.

D/4 = b'^2 - ac (ax^2+2b'x+c=0)