equation
solue linear equation
2x =5y + 4
3x-2y + 16 =0
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Answer:
given,
2x=5y+4
3x-2y+16=0
now,
2x-5y=4....................(1)*3
6x-15y=12.................(2)
3x-2y=-16..................(3)*2
6x-4y=-32..................(4)
now, Subtract equation number 2 from 4
6x-4y=-32
-(6x-15y=12)
-4y+15y=-32-12
11y=-44
y=-4
put the value of y in equation 2
6x-4*(-4)=32
6x+16=32
6x=32-16
6x=16
x=16/6
x=8/3
hence, the value of x=8/3 and y=-4
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