Equation to find the sum of consecutive numbers from 11 to 20
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go by airthmatic progration
Sn = n/2{2a+(n-1)d}
here n = 20-11 +1=10 &d= 1 &a= 11
thus, Sn = 10(22+9)=310
Sn = n/2{2a+(n-1)d}
here n = 20-11 +1=10 &d= 1 &a= 11
thus, Sn = 10(22+9)=310
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