Equation to the normal to the curve y = f(x) at (x, y)is
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Correct option is
A
y=e
a(x−1)
Slope of tangent at any point P(x,y) is
dx
dy
∝y
⇒
dx
dy
=ky⇒y=e
k(x−1)
since a(y−1)+(x−1)=0 is normal at (1,1)⇒k=1
Hence f(x)=y=e
a(x−1)
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