equation (x+1)2(as square) +x2=0 has how many roots
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The equation has one real root.
And the root is -1/2.
Step-by-step explanation:
(x + 1)^2 - x^2 = 0
x^2 + 2x + 1 -x^2 = 0
2x + 1 = 0
x = -1/2
Thus, the given equation has only one real root.
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