Math, asked by thenotorious3, 8 months ago

Equation (x + 1) ^ 2 - x ^ 2 = 0 has real oot * (s)
What’s the answe guys
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Answered by anindyaadhikari13
3

Answer:

The answer is One.

Step-by-step explanation:

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Answered by Anonymous
5

SOLUTION:-

(x + 1)² - x² = 0

x² + 2x + 1 - x² = 0

2x + 1 = 0

2x = -1

x = -1/2

-1/2 is real roots of equation (x + 1)² - x² = 0

More information:-

Real roots

Real roots can be expressed as real numbers. Sometimes this is simple, as with √4=2, sometimes a bit more complex and we approximate, as with √3=1.7320508.

Imaginary roots

Imaginary roots are expressed in imaginary numbers, and the simplest imaginary number is i=√−1.

Most imaginary numbers can be expressed in the form 'a+bi where a and b are real numbers, but the whole number is imaginary because of the presence of i.

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