Question

equation (x+1)^2-x^2=0 has______ real roots

Answer 1

Answer:

2

Step-by-step explanation:

Since the degree of this polynomial is 2,hence it had only 2 roots

Answer 2

Step-by-step explanation:

THE GIVEN EQUATION IS

$( {x + 1})^{2} - {x}^{2} = 0$

${x}^{2} + 2x + 1 - {x}^{2}$

$2x + 1$

IT HAS ONLY ONE REAL ROOT

I.E

$\frac{ - 1}{2}$

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