Math, asked by kalpeshrohera, 1 month ago

Equation (x+1)2 – x2 = 0 has _____ real root(s).​

Answers

Answered by rosreva
1

Step-by-step explanation:

(x+1)^2 - x^2

x^2 + 2x +1 -x^2

2x+1

x= -1/2

Answered by tennetiraj86
2

Step-by-step explanation:

Given equation is (x+1)²-x²=0

=>+2x+1-x²=0

=>2x+1=0

It is a linear equation.

=>2x=-1

=>x=-1/2

It has real root .it is a linear equation

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