Question

Equation X + 1 square minus x square is equals to zero has real roots
pls ans with steps

Answer 1

Answer:

here's your answer dear

Step-by-step explanation:

Given, 

(x−1)2+(x−2)2+(x−3)2=0

⇒x2−2x+1+x2−4x+4+x2−6x+9=0

⇒3x2−12x+14=0

Let D be the discriminant of the obtained quadratic equation.

D=(−12)2−4×14×3=144−168=−24

Since the value of discriminant is negative, the equation does not have any real roots