Equation x+y+z=6 , x-y+z=2 , 2x+y-z=1 have solution :
a) x=1 ,y=1, z=1
b) x=1 ,y=3 ,z=2
c) x=2, y=1 ,z=3
d) x=1, y=2 ,z=3
Answers
Answered by
0
Step-by-step explanation:
have,
x+y+z=6,x−y+z=2,2x+y−z=1
Thus A=
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1
1
2
1
−1
1
1
1
−1
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X=
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x
y
z
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,B=
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6
2
1
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Now Solve A to get A=6
Now x=
A
A
x
=
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1
1
2
1
−1
1
1
1
−1
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6
2
1
1
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1
1
1
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=
6
6
=1
y=
A
A
y
=
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1
1
2
1
−1
1
1
1
−1
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1
1
2
6
2
1
1
1
−1
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=
6
12
=2
z=
A
A
z
=
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1
1
2
1
−1
1
1
1
−1
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1
1
2
1
−1
1
6
2
1
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=
6
18
=3
Thus x=1,y=2,z=3
Answered by
0
Answer:
d is the right answer.....
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