Math, asked by ravisinghsengar, 8 months ago

Equation x+y+z=6 , x-y+z=2 , 2x+y-z=1 have solution :
a) x=1 ,y=1, z=1
b) x=1 ,y=3 ,z=2
c) x=2, y=1 ,z=3
d) x=1, y=2 ,z=3​

Answers

Answered by jothika132002
0

Step-by-step explanation:

have,

x+y+z=6,x−y+z=2,2x+y−z=1

Thus A=

1

1

2

1

−1

1

1

1

−1

X=

x

y

z

,B=

6

2

1

Now Solve A to get A=6

Now x=

A

A

x

=

1

1

2

1

−1

1

1

1

−1

6

2

1

1

−1

1

1

1

−1

=

6

6

=1

y=

A

A

y

=

1

1

2

1

−1

1

1

1

−1

1

1

2

6

2

1

1

1

−1

=

6

12

=2

z=

A

A

z

=

1

1

2

1

−1

1

1

1

−1

1

1

2

1

−1

1

6

2

1

=

6

18

=3

Thus x=1,y=2,z=3

Answered by tiyas12
0

Answer:

d is the right answer.....

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