Question

equation (x²+2)²-x²=0 has number of real roots equal to:​

Answer 1

Answer:

Sine the given equation is of degree 4 , therefore it should have 4 real roots

Answer 2

Step-by-step explanation:

(x²+2)²-x²=0

x²+4+4x-x²=0

4x=-4

x=-1