Math, asked by rituparekh1984, 3 months ago

Equation x²+5x+8=0 has no real roots. ​

Answers

Answered by pulakmath007
12

SOLUTION

TO PROVE

Equation x² + 5x + 8 = 0 has no real roots.

CONCEPT TO BE IMPLEMENTED

For an given equation ax² + bx + c = 0

Discriminant = D = b² - 4ac

  • D = 0 gives two roots are real and equal

  • D > 0 gives two roots are real and unequal

  • D < 0 gives two roots are imaginary

EVALUATION

Here the given equation is x² + 5x + 8 = 0

Comparing with ax² + bx + c = 0 we get

a = 1 , b = 5 , c = 8

Discriminant = D =

= b² - 4ac

 = {5}^{2}  - 4 \times 1 \times 8

 = 25 - 32

 =  - 7 &lt; 0

Hence both roots are imaginary

Hence the Equation x² + 5x + 8 = 0 has no real roots.

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Answered by charaniyaminaxi
2

Answer:

true because it has no real roots.

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