Equations 5x+ 2y = 16 and 7x - 4y = 2 have :
(A) no solution
(C) infinitely many solutions
(B) a unique solution
(D) none of these
Answers
Answer:
hey mate your answer is..
Step-by-step explanation:
option (B) a unique solution.......
Equations 5x+ 2y = 16 and 7x - 4y = 2 have (B) a unique solution
Step-by-step explanation:
Given:
equations are
5x+ 2y = 16 & 7x - 4y = 2
To find:
nature of the solution
Solution:
We have to look at the solutions first, for that we use the elimination method for the linear equations
5x-2y=16
Multiplying this linear equation by 2
we get 10x-4y=32...(i)
7x - 4y = 2....(ii)
Subtracting equation (ii) from (i)
10x-4y=32
7x-4y=2
(-) (+) (-)
3x = 30
∴ 3x=30
∴ x =30/3
∴ x = 10
substituing the value of x in an original equation
7x - 4y = 2
7(10) -4y=2
70-4y=2
70-2= 4y'
68=4y
∴ 4y = 68
∴ y = 68/4
∴ y = 17
The solution of the linear equations 5x+ 2y = 16 and 7x - 4y = 2 is {10,17}
As we see the solution is non-zero and the equations are consistent and determinant. Thus the solution is unique
It cannot be infinite or zero as no solution
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