Math, asked by harsh4954, 8 months ago

Equations 5x+ 2y = 16 and 7x - 4y = 2 have :
(A) no solution
(C) infinitely many solutions
(B) a unique solution
(D) none of these

Answers

Answered by rajsingh24
6

Answer:

hey mate your answer is..

Step-by-step explanation:

option (B) a unique solution.......

Answered by jenisha145
1

Equations 5x+ 2y = 16 and 7x - 4y = 2 have (B) a unique solution

Step-by-step explanation:

Given:

equations are

5x+ 2y = 16 & 7x - 4y = 2

To find:

nature of the solution

Solution:

We have to look at the solutions first, for that we use the elimination method for the linear equations

5x-2y=16

Multiplying this linear equation by 2

we get 10x-4y=32...(i)

7x - 4y = 2....(ii)

Subtracting equation (ii) from (i)

10x-4y=32

7x-4y=2

(-) (+)  (-)  

3x    = 30

∴ 3x=30

∴ x =30/3

∴ x = 10

substituing the value of x in an original equation

7x - 4y = 2

7(10) -4y=2

70-4y=2

70-2= 4y'

68=4y

∴ 4y = 68

∴ y = 68/4

∴ y = 17

The solution of the linear equations 5x+ 2y = 16 and 7x - 4y = 2 is {10,17}

As we see the solution is non-zero and the equations are consistent and determinant. Thus the solution is unique

It cannot be infinite or zero as no solution

#SPJ3

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