Question

equations by factorisation
i ) x-3/x =2

Find the roots of the following quadratic​

Answer 1

Answer:

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Answer 2

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Given:

$x - \frac{3}{x} = 2$

Take the LCM.

$\frac{ {x}^{2} - 3 }{x} = 2$

${x}^{2} - 3 = 2x$

The quadratic equation formed is...

${x}^{2} - 2x - 3 = 0$

By splitting the middle term,

${x}^{2} + x - 3x - 3 = 0$

$x(x + 1) - 3(x + 1) = 0$

$(x - 3)(x + 1) = 0$

And the zeroes are...

$x = 3 \: or \: - 1$

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