Question

equations of the line passing through A (x1,y1) and parallel to the line ax+by+c=0 is a (x-x1)+b(y-y1)=0 hence find the equation of the line passing through (1,1) and parallel to the line 15x+8y+1947=0​

Answer 1

The equation of the line passing through (1, 1) and parallel to the line 15x + 8y + 1947 = 0 is 15x + 8y - 23 = 0

• Given,

          Equation of the line passing through $(x_{1}, y_{1})$ and parallel to

ax + by + c = 0 is

                   $a(x-x_{1}) + b(y-y_{1}) = 0----------------(1)$

• Here,

                   a = 15, b = 8,  $(x_{1}, y_{1})=(1,1)$

• Substituting above values in (1), we get

                     15(x - 1) + 8(y - 1) = 0

                     15x - 15 + 8y - 8 = 0

                     15x + 8y - 23 = 0