Question

Equations of two curves Q and R are given as follows: Q(t) = (1-1)³ P₁ + (31³-6t²+4) P. + (-3t³ + 3t² + 3t+1) P₁+ t³ P. R(t) = (1-1)³ P₁+ (31³-6t²+4) P₁ + (-3t³ + 3t² + 3t+1) P. + ³ P. For both the curves 0 < t < 1. Are both the curves C continuous at Q(1) and R(0)? Why or why not? Are they both C and G continuous at Q(1) and R(0)? Why or why not? Are they both C and G continuous at Q(1) and R(0)? Why or why not? Explain your answers.

Answer 1

Answer:

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Answer 2

Answer:

History of Broadband Impedance Matching (category Computing and electronics) (section The Broadband Matching Problem)

impedance function Z1 has R1>0 when σ>0 and X1=0 when ω=0. Positive real impedance functions occur as the ratio of specific polynomials in the complex frequency

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