Question

Equilateral triangle ABD and ACE are drawn on sides AB and AC respectively of a ∆ABC outside it. Prove that:
1. Angle DAC = Angle EAB
2. DC = BE

Answer 1

Answer:

1. ac=ab(common side),angle A=A(common angle),angle ace=and(equal side),∆abd=~∆ace by asa rule 2. from cpct rule dc=be above proved in triangles