equilateral triangle are drawn on the three sides of a triangle Show that the areas of the triangle on the hypothesis is equal to the sum of the areas of triangles on the other two sides
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Let a right triangle BAC in which ∠A is right angle and AC = y, AB = x.
Three equilateral triangles ΔAEC, Δ AFB and ΔCBD are drawn on the three sides of ΔABC. Again let area of triangles made on AC, AS and BC are A1, A2 and A3, respectively.
To prove A3 = A1 + A2
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