Question

Equilibrium constant for the reaction is 4.0 what will be the equilibrium constant for the reverse reaction

Answer 1

For the reverse reaction eqilibrium constant will be 1/4 i. e. 0.25

Answer 2

Answer: The equilibrium constant for the reverse reaction will be 0.25

Explanation:

Equilibrium constant for a reaction is the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

For the reaction:

$aA+bB\rightarrow cC+dD$

Equilibrium constant is given as:

$K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

When the above reaction is reversed, the reverse equilibrium constant will be the reciprocal of the forward equilibrium constant.

$K_{forward}=4\\\\K_{backward}=\frac{1}{K_{forward}}=\frac{1}{4}=0.25$

Hence, the equilibrium constant for the reverse reaction will be 0.25