Equilibrium: Please solve the question in the image. Ans. is 0.66 M but I need the solution.
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WILL MARK BRAINLIEST
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The reaction starts when the tap is open .
So, when the tap opens the volume of the actual mixture will be = 1+3 = 4 lt.
so, the initial concentration of a is = moles of a /vol. of solution (in lt)
= 2/4 = 0.5 mole
the initial concentration of b is = moles of b/vol.of solution (in lt)
= 4/4 = 1 mole
a2 + b2 - 2ab
at t=0 = 0.5 1 0
at t=equilibrium = 0.5 -x 1-x 2x
kc = (2x)^2/(0.5-x)(1-x)
given that kc = 4
solve this you get x = 0.33
but as you see that at equilibrium the concentration of ab is 2x hence ,
the required answer is 2*0.33 = 0.66 moles
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