Question

Equimolal solutions of A and B show depression in freezing point in the ratio of 2:1.A remains in normal state in solution.B will be in..............state.

Answer 1

B will be in associated state.

Explanation:

Formula used :  

$\Delta T_f=i\times K_f\times m$

where,

$\Delta T_f$ = Depression in freezing point

i = Van't Hoff factor

$K_f$ = freezing point constant

m = molality

$\frac{\Delta T_f_{A}}{\Delta T_f_{B}}=\frac{i_{A}\times K_f\times m}{i_{B}\times K_f\times m}$

$\frac{2}{1}=\frac{1}{i_{B}}$

$i_{B}=\frac{1}{2}$

Thus B will be in associated state.

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