Question

Equivalent amounts of H2 and I2 are heated in a closed vessel till equilibrium is
obtained if 80% of the hydrogen can be converted to HI, the Kc at this same
temperature is ....
1) 64
2) 16
3) 0.25
4) 40​

Answer 1

Answer:

1) 64

Explanation:

According to the given question,

Use Formula,

Kc = [HI] square divided by [H2] multiplied by [I2] = (2x) square divided by (1-x) square

Given X=80 % or 0.80

Therefore, you can get the answer by solving the equation

Kc= [2 * 0.80] (square) divided by (1 - 0.80)(square)= 64

The value of Kc is 64.

Answer 2

The Kc at this same  temperature is  64

Explanation:

H2 + I2        ⇆       2HI

1         1                     0

(1- 0.8 ) (1- 0.8 )       2 X 0.8

= 0.2     = 0.2           = 1.6

Kc = [ HI ]² /  [H2] [I2]

     = 1.6 X 1.6 / 0.2 X 0.2

Kc = 64

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the temperature of a city during a week was 35 temperature 36 temperature 34th temperature and 44 temperature what was the average daily temperature of the town for the week​

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