Equivalent conductance of nacl hcl and ch3coona at infinite dilution
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Hi,
This question is lacking some values which can be used for it to be solved.
But if this question can be the way I think, then I will give you the solution to it.
Please consider the question given below.
if equivalent conductance at infinite dilution of Nacl, Hcl and CH3COONa are 126,45,426 and 91.0 respectively conductance of acetic acid at infinite dilution.
Then λ CH3COOH = λCH3COONa + λHCl - λNaCl =
= 91 + 426 – 126.45 = 390.55
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