Question

Equivalent conductance of saturated BaSO4 is 400 ohm-1 cm2 eqvt-1 and specific conductance is 8×10 to the power-5 ohm-1 cm-1 the Ksp of BaSO4 is

Answer 1

ans is 2 into 10 to the power minus 4
this answer can be dried by the its solubility equal to
k×1000/^eq

Answer 2

Answer : The value of $K_{sp}$ of $BaSO_4$ is, $4\times 10^{-8}$

Solution :

First we have to calculate the solubility of a $BaSO_4$ salt.

Formula used :

$Solubility=\frac{k\times 1000}{\Lambda}$

where,

k = specific conductance = $8\times 10^{-5}ohm^{-1}cm^{-1}$

$\Lambda$ = equivalent conductance = $400ohm^{-1}cm^{2}eq^{-1}$

Now put all the given values in the above formula, we get the solubility.

$Solubility=\frac{(8\times 10^{-5}ohm^{-1}cm^{-1})\times 1000}{400ohm^{-1}cm^{2}eq^{-1}}=2\times 10^{-4}$

Now we have to calculate the value of $K_{sp}$ of $BaSO_4$

The equilibrium reaction will be,

$BaSO_4\rightleftharpoons Ba^{2+}+SO_4^{2-}$

The expression of solubility product, $K_{sp}$ will be,

$k_{sp}=[Ba^{2+}][SO_4^{2-}]$

$k_{sp}=s\times s$

$k_{sp}=s^2$

where, s is solubility

$k_{sp}=(2\times 10^{-4})^2=4\times 10^{-8}$

Therefore, the value of $K_{sp}$ of $BaSO_4$ is, $4\times 10^{-8}$