Equivalent of a metal carbonate is 69 g Find equivalent weight of metal.
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let the metal carbonate be:
M2(CO3)X
molar mass = 2M + 60x
moles = 6.9/( 2M + 60x)
Now,
Molarity = Normality/V.F
= 2/1 = 2
MV = moles
moles = (2*60-20*1)/1000 = 100/1000 = 0.1 { 20 mm neutralized by OH-}
6.9/Z = 0.1
Z = 6.9/0.1
Z = 69
Molar mass of metal carbonate is hence, 69.
moles of metal = 0.1*2 = 0.2
Eq. Weight = moles x valence factor.
= 0.2 x 2
= 0.4
M2(CO3)X
molar mass = 2M + 60x
moles = 6.9/( 2M + 60x)
Now,
Molarity = Normality/V.F
= 2/1 = 2
MV = moles
moles = (2*60-20*1)/1000 = 100/1000 = 0.1 { 20 mm neutralized by OH-}
6.9/Z = 0.1
Z = 6.9/0.1
Z = 69
Molar mass of metal carbonate is hence, 69.
moles of metal = 0.1*2 = 0.2
Eq. Weight = moles x valence factor.
= 0.2 x 2
= 0.4
Roop80880:
But answer is 39
Answered by
2
Answer:
39
Explanation:
Equivalent mass of a metal is x
Equivalent mass of the metal carbonate= eq.mass of metal + eq.mass of carbonate
69 = x + 60/2
x = 39
equivalent CO3 = 12+16x3= 60/2=30
The reason we divide it in 2 is the charge of the carbonate anion -2
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