equivalent resistance
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5.41ohm , resistance b/w D&B =12(10+2)
now we have two parallel resistance b/w D&B
12OHM &12OHM
final resistance will be b/w D&B will be 6ohm
now that 6ohm is in series with 2ohm (resistance b/w c&d) which will be 8ohm final.
now
4 resistance are connected to point C in parallel
which will be
(1/8)+(1/3)+(1/4)+(1/3)=1/R
so R b/w c&b will be 24/17
now 24/17 is in series with the 4ohm resistance (which is between A&C)
so final will be (24/17)+4= 92/17=5.41ohm
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