Physics, asked by siddharth446, 11 months ago

equivalent resistance between a and b .​

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Answered by BellaSnowflake
3

All the resistors are in series.

So, R = 2R + 2R + 2R + 2R + 2R

     R = 10R

Hope this helps...   : )


BellaSnowflake: But, if the point is a junction, then 2R + 2R and 2R + 2R are in parallel. So, 1/4R + 1/4R = 2/4R. The total resistance will be 2R. Now, the equivalent resistance of the circuit will be 2R + 2R = 4R.
Answered by nain31
4
 \bold{RESISTANCE}

Resistance is the obstruction offered in the path of current.

For a series combination , total resistance is the sum of all resistances consitituting the ciruit.

 \bold{R_s = R_1 + R_2 + R_3 + n \: th \: term}

When circuit is series,

◼Current have only one path to flow, so same current forceach resistor.

◼Since, potential difference is directional proportional to resistance , so it varies tbrough circuit.

◼For a parallel combination ,

Total resistance is the sum of reciprocs of all resistances.

When circuit is parllel,

◼Current have only several pathd to flow, so current for each resistor varies.

◼Since, potential difference is directional proportional to resistance , so through circuit remains same

 \bold{\frac{1}{R_p}= \frac{1}{R_1 }+ \frac{1}{R_2 } + \frac{1}{R_3 } + n \: th \: term}

◼To find resistance between A and B

Since , all resistor are in series to the resistors in parallel.

 \bold{\frac{1}{R_p}= + \frac{1}{2} + \frac{1}{4 } + \frac{1}{2}}

 \bold{\frac{1}{R_p}=\frac{5}{4}}

 \bold{R_p = 1.25 \: ohm}

Since, resistor with 2 ohm resistance is in series so,

 \bold{\mathsf{R_s = 2 + 1.25 Ohm}}

 \boxed{\mathsf{R = 3.25 \: ohm}}
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