Physics, asked by sanchig31, 9 months ago

Equivalent resistance of four resistors R1, R2, R3, and R4 connected in parallel can be given as


1/R1 + 1/R2 + 1/R3 + 1/R4

R1 + R2 + R3 + R4

(R1 + R2) / (R3 + R4)

None of these

Please answer this question with step by step explanation. .​

Answers

Answered by gauribharsakle69
3

Answer:

Equivalent resistance of 4 Resistors in parallel can be given by:

1/R=1/R1+1/R2+1/R3+1/R4

hope it helps......

Answered by ArunSivaPrakash
1

The equivalent resistance of four resistors R₁, R₂, R₃, and R₄ connected in parallel can be given as 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄ (option-1).

  • Resistors in a circuit can be arranged in series and in parallel combinations.
  • In a series combination, the overall resistance of the circuit increases, and current flow through the circuit decreases.
  • In parallel arranged conditions, the equivalent resistance decreases, and current flow through the circuit increases.
  • When 4 resistors of resistance R₁, R₂, R₃, and R₄ are connected in parallel combinations. Then equivalent resistance is -
  • 1/R' =  1/R₁ + 1/R₂ + 1/R₃ + 1/R₄

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