Question

Equivalent resistance of the circuit shown above
will be :-

(1) 3.33 Ω
(2) 1.25 Ω
(3) 2.5 Ω
(4) 4 Ω
Please refer the image given ​

Answer 1

Given :

The circuit diagram is given in the image attached with the question.

To find :

The equivalent resistance of the circuit.

Solution :

Formulas to be used :

• Series : R = R₁ + R₂
• Parallel : $\frac{1}{R} = \frac{1}{R_1} +\frac{1}{R_2}$

R₁ and R₂ are in series

∴ Rs₁ = R₁ + R₂

Rs₁ = 2 + 2

Rs₁ = 4Ω

Rs₁ and R₃ are in parallel

$\frac{1}{R_p_1} = \frac{1}{R_s_1} +\frac{1}{R_3}$

$\frac{1}{R_p_1} = \frac{1}{4} +\frac{1}{2}$

$\frac{1}{R_p_1} = \frac{1+2}{4}$

$\frac{1}{R_p_1} = \frac{3}{4}$

Rp₁ = 4/3Ω

Rp₁ and R₄ are in series

Rs₂ = Rp₁ + R₄

Rs₂ = 4/3 + 2

Rs₂ = (4 + 6)/3

Rs₂ = 10/3

Rs₂ and R₅ are in parallel

$\frac{1}{R_e_q} = \frac{1}{R_s_2} + \frac{1}{R_5}$

$\frac{1}{R_e_q} = \frac{1}{\frac{10}{3} } + \frac{1}{2}$

$\frac{1}{R_e_q} = \frac{3}{10} + \frac{1}{2}$

$\frac{1}{R_e_q} = \frac{3+5}{10}$

$\frac{1}{R_e_q} = \frac{8}{10}$

$\frac{1}{R_e_q} = \frac{4}{5}$

Req = 5/4Ω

Req = 1.25Ω

Therefore the equivalent resistance is 1.25Ω.

Answer 2

Answer:

1.25

Explanation:

since equivalent resistance of the circuit is 1.25 ohm