Question

Equivalent values of two capacitors connected in series

Answer 1

When capacitors are connected in series, the total capacitance is less than any one of the series capacitors' individual capacitances. If two or more capacitors are connected in series, the overall effect is that of a single (equivalent) capacitor having the sum total of the plate spacings of the individual capacitors.

Answer 2

Answer:

$\bigodot\mathtt \pink{\frac { 1 } { C } = \frac { 1 } { C _ { 1} } + \frac { 1 } { C _ { 2 } } + \frac { 1 } { C _ { 3 } } + \cdots + \frac { 1 } { C _ { n } }} \\ \bigodot\mathtt \red{\frac { 1 } { C } = \frac { 1 } { C _ { 1} } + \frac { 1 } { C _ { 2 } } + \frac { 1 } { C _ { 3 } } + \cdots + \frac { 1 } { C _ { n } }} \\ \bigodot\mathtt \blue{\frac { 1 } { C } = \frac { 1 } { C _ { 1} } + \frac { 1 } { C _ { 2 } } + \frac { 1 } { C _ { 3 } } + \cdots + \frac { 1 } { C _ { n } }} \\ \bigodot\mathtt \orange{\frac { 1 } { C } = \frac { 1 } { C _ { 1} } + \frac { 1 } { C _ { 2 } } + \frac { 1 } { C _ { 3 } } + \cdots + \frac { 1 } { C _ { n } }}$