Question

Equivalent volume of Co, in the following reaction
will be
8.
Na2CO3 + HCl → NaCl + H2O + CO2
(1) 2.24 L
(2) 11.2 L
(3) 44.8L
(4) 5.6 L​

Answer 1

Explanation:

Answer :-

44.8L

...........

Answer 2

(2) 11.2 L

Explanation:

$Na_2CO_3+2HCl\rightarrow 2NaCl+H_2O+CO_2$

Mass of carbon=12 g

Mass of Oxygen=16 g

Mass of $CO_2=12+2(16)=12+32$

Mass of $CO_2=44 g$

We know that

1 mole of Carbon dioxide=22.4 L

Mass of carbon dioxide=1 mole of carbon dioxide=22.4 L

Carbonate change into carbon dioxide by losing 2 electrons and 2 hydrogen ion change into $H_2$ by gaining 2 electrons.

Therefore, 2 electrons are involved in oxidation reduction

Therefore, the equivalent volume of carbon dioxide=$\frac{22.4}{2}=11.2 L$

Option (2) is true.

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