Question

Equivalent weight of a dibasic acid is 12 ITC molecular weight is​

Answer 1

answer : 24g/mol

explanation : you should know that equivalent weight is ratio of molecular weight and n-factor.

i.e., equivalent weight = Molecular weight/n-factor.

n-factor is

1. basicity of acid,
2. acidity of base,
3. change in oxidation number in redox reaction,
4. valency of atom etc..

here given equivalent weight of dibasic acid is 12.

for dibasic acid => n - factor = 2

then, equivalent weight = molecular weight/2

or, 12 = molecular weight/2

or, molecular weight = 24 g/mol.

hence, molecular weight of acid is 24g/mol.

Answer 2

We know,

Normality = Molarity × Basicity of Acid.

No. of gram equivalent/Volume of sol. = No. of moles/Volume of solution × Basicity of Acid

∴ mass/Equivalent mass = mass/molar mass × Basicity of Acid

∴ Molar Mass = Equivalent weight × Basicity of Acid.

∴ Molar mass = 12 × 2

∴ Molar mass = 24 g/mole.

Hence, the molar mass of the given compound is 24 g/mole.

Hope it helps.