Question

Equivalent weight of a metal chloride is 75.5. How
many moles of NaOH is required to completely
precipitate the one mole metal hydroxide. Atomic
weight of the metal is 120.
Numeric Answer:​

Answer 1

Answer:

The atomic weight of metal = molecular weight - the atomic weight of Cl

Atomic weight of metal= 74.5−35.5

Atomic weight of metal= 39

Equivalent weight =

1

39

Equivalent weight = 39.0