Question

equivalent weight of bayer's reagent

Answer 1

We know that in basic medium KMnO4 (Mn oxidation state=7)converts into MnO2 (Mn oxidation state=4) so change in oxidation is 3.

Equivalent weight = molecular weight÷change in oxidation state

Molecular mass of KMnO4=158

Equivalent weight of KMnO4=158÷3=52.66
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