Question

equivalent weight of bivalent metal is 32.7 . molecular weight of its chloride is.

Answer 1

molecular weight of its chloride will be it's double

I think the answer is correct

Answer 2

Answer : The molecular weight of its chloride is, 136.4 g/mole

Solution : Given,

Equivalent weight of bivalent metal = 32.7 g/eq

The metal is bivalent that means valency of metal is, 2

The compound is, $MCl_2$

The anion is chloride and the molar mass of chloride is, 71 g/mole

Formula used :

$E=\frac{M}{n}$

where,

E = equivalent weight

M = molecular weight

n = valency of metal atom

First we have to calculate the molecular weight of metal.

$\text{Equivalent of metal}=\frac{\text{Molecular weight of metal}}{n}$

$32.7g/eq=\frac{\text{Molecular weight of metal}}{2mole/eq}$

$\text{Molecular weight of metal}=65.4g/mole$

Now we have to calculate the molecular weight of $MCl_2$

$\text{Molecular weight of }MCl_2=\text{Molecular weight of M}+\text{Molecular weight of }Cl_2$

$\text{Molecular weight of }MCl_2=65.4+71=136.4g/mole$

Therefore, the molecular weight of its chloride is, 136.4 g/mole