Equivalent weight of ca in calcium oxide
Answers
Answer:
Hydrogen forms binary hydrides with
many electropositive elements including
metals and non-metals. It also forms ternary
hydrides with two metals. E.g., LiBH4
and
LiAlH4
. The hydrides are classified as ionic,
covalent and metallic hydrides according
to the nature of bonding. Hydrides formed
with elements having lower electronegativity
than hydrogen are often ionic, whereas with
elements having higher electronegativity
than hydrogen form covalent hydrides.
Ionic (Saline) hydrides: These are
hydrides composed of an electropositive
metal, generally, an alkali or alkaline-earth
metal, except beryllium and magnesium,
formed by transfer of electrons from metal
to hydrogen atoms. They can be prepared
by the reaction of elements at about 400°
C. These are salt-like, high-melting, white
crystalline solids having hydride ions (H−)
and metal cations (Mn+).
Answer:
40g
Explanation:
Equivalent weight of any metal in a metal oxide is the amount of metal which reacts with 8g of oxygen.
In CaO we can clearly see that one mole of Ca will react with one mole of O.
therefore 40g of Ca will react with 8g of O.