Question

equivalent weight of h2so4 in the reaction h2so4 ---> h2s is
1. M/2
2. M/3
3. M/4
4. M/8.​

Answer 1

Answer: M/8

Explanation: H2SO4 = H2S

n=6 n= -2

therefore nf = 8

:- equivalent weight of H2SO4 = M/nf

= M/8

Answer 2

The equivalent weight of $H_2SO_4}$ is, (4) $\frac{M}{8}g.eq$

Explanation:

Equivalent weight : It is the molar mass of a substance divided by the number of equivalents in the substance.

The given reaction is :

$H_2SO_4\rightarrow H_2S$

The complete balanced chemical reaction in acidic medium will be:

$H_2SO_4+8H^++8e^-\rightarrow H_2S+4H_2O$

Number of electrons involved in this reaction = 8

Let the molar mass of $H_2SO_4$ be, M

$\text{Equivalent weight of }H_2SO_4=\frac{\text{Molar mass of }H_2SO_4}{\text{Number of electrons involved in this reaction}}=\frac{M}{8}g.eq$

Therefore, the equivalent weight of $H_2SO_4}$ is, $\frac{M}{8}g.eq$

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