Equivalent weight of K2CrO4 when it reacts with AgNO3 to give Ag2CrO4 is?
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Answer:
K2CrO4+8H------>2K+Cr3+4H2O
Here Cr3 6+ reduced to Cr 3+ so 3 electron are involved in the reaction
Thus equivalent weight =294.2÷3= 98.6
chauhanavni14:
But if the reaction is not given then how will we solve it?
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