Question

Equivalent weight of N, in the change N2 + NH3 is
(1) 28/6 (2) 28 (3) 28/2 (4) 28/3​

Answer 1

Answer:

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Answer 2

Answer:

Solution:- (D)

3

17

N

2

⟶NH

3

Oxidation no. of N in N

2

=0

Oxidation no. of N in NH

3

=−3

Valence factor = no. of atoms × change in oxidation no.

∴ Valence factor for NH

3

=1×∣0−(−3)∣=3

Molecular weight of NH

3

=17g

As we know that,

eq. wt.=

valence factor

mol. wt.

∴ Equivalent weight of NH

3

for the given change =

3

17

Hence for the given change, the equivalent weigt of NH

3

will be

3

17

.