Equivalent weight of N2 and NH3 in the following reaction N2 + H2 NH3 will be
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Oxidation number of N in N2= Zero
Oidation number of N in NH3= -3
Change in oidation number is by 3 units for each N atom , so for N2 molecule it is by 6 units
Therefore equivalent weight =M/6 =28/6
Oidation number of N in NH3= -3
Change in oidation number is by 3 units for each N atom , so for N2 molecule it is by 6 units
Therefore equivalent weight =M/6 =28/6
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