Question

Equivalent weight of Na2Co3

Answer 1

HELLO THERE!

Here's the formula for calculation of equivalent weight, which will be used in this case:

Equivalent weight

$E = \frac{M}{n\times V}$

Where, M is the molecular weight of the compound, n is the number of cations, and V is the valency of cation.

In Sodium carbonate, the number of cations is 2, valency of cation (Na) is 1, and molecular weight of sodium carbonate is (2×23)+12+48 = 106

So,

$E = \frac{106}{2\times1} = 53$

Thanks!

Answer 2

Answer:

Here's the formula for calculation of equivalent weight, which will be used in this case:

Equivalent weight

E = E= n×VM

Where, M is the molecular weight of the compound, n is the number of cations, and V is the valency of cation.

In Sodium carbonate, the number of cations is 2, valency of cation (Na) is 1, and molecular weight of sodium carbonate is (2×23)+12+48 = 106

So,

E = 106 = 53E= 2×1106 =53