Chemistry, asked by swaddmasteeh3549, 1 year ago

equivalent weight of silver nitrate

Answers

Answered by JunaidMirza
46
Ag⁺ + NO³⁻ → AgNO₃
Equivalent weight = Molecular weight / Total charge on +ve ion
= 170/1
= 170
Answered by skyfall63
19

The equivalent weight of silver nitrate is 170.

Explanation:

The molecular formula for silver nitrate is AgNO_3. If we have a look at the chemical equation of formation of the silver nitrate is

\mathrm{Ag}^{+}+\mathrm{NO}^{3-} \rightarrow \mathrm{AgNO}_{3}

We know that, the formula for chemical equation is division of Molecular weight and Total charge on positive on.

For AgNO_3, Molar mass of Silver is = 108

Molar mass of Nitrogen is = 14

Molar mass of Oxygen is =16

\Rightarrow 16 \times 3 = 48

Then,

AgNO_3 =108+14+48=170

Therefore, Equivalent weight of AgNO_3 is given below:

\Rightarrow \frac{170}{1} = 170

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