equvalent weight of kmno4
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31.6 grams
The Mn in KMnO4 exists in +7 state. In Acidic medium, This Mn +7 goes to Mn+2 state and hence there is a net gain of 5 electrons. Therefore,The Equivalent Weight = 158/5 = 31.6 grams.
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Equivalent weight=Molecular weight /n factor
Molecular weight of Kmno4=158 gm/mol
N factor = 5.
Equivalent weight=158/5=31.6gm
Answer=
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