Question

equvilant resistace when the following is connected in parallel
6 ohm and 10^6 ohm ​

Answer 1

HeRe Is Your Ans ⤵

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$\frac{1}{r} = \frac{1}{r1} + \frac{1}{r2} \\ \\ \frac{1}{r} = \frac{1}{6} + \frac{1}{ {10}^{6} } \\ \\ \frac{1}{r} = \frac{1}{6} + \frac{1}{1000000} \\ </p><p></p><p>\frac{1}{r} = \frac{1}{0.166667} \\ \\ r = 0.166667$

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