Physics, asked by rudra221, 1 month ago

equvilant resistance
please tell ans ​

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Answered by NewGeneEinstein
2

In parallel

\boxed{\sf \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\dots}

\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{1}{1}+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}

\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{12+6+4+3}{12}

\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{25}{12}

\\ \sf\longmapsto R=\dfrac{12}{25}

\\ \sf\longmapsto R=0.4\Omega

In series:-

\\ \sf\longmapsto R=R_1+R_2

\\ \sf\longmapsto R=0.4+0.6

\\ \bf\longmapsto R=1\Omega

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