Question

erature T.
equal to
cules of
217. When a system is taken from stat
'b' along the path 'acb', it is found tha
of heat Q = 200 J is absorbed by +
and a work W = 80J is done by i
path 'adb', Q = 144J. The work done
path 'adb' is
I state a to state
ind that a quantity
bed by the systern
by it. Along the
ork done along the
(1780
223. In a cu
the ma
les of a
(1) 6J
(2) 12 J
(3) 18 J 44)24J
(1) TT
8. In the above question, if the work done on the
system along the curved path 'ba' is 52), heat
absorbed is
(1) -140 J
127-172 J
(3) 140 J
(4) 172 J
224. The
cyclic
(1) PL
be
(2) 2
(3) 3
(4) 4
ed with 219. In question No. 217, if U - 40J, value of Ujwill
ixture is:
1.67
(1) - 50 J
(2) 100 J
(3) -120 J
MICS,
147160 J
229. tñ question No. 217, if U, = 88 J, heat absorbed |
for the path 'db' is
(1) -72 J
042) 72 J
(3) 144 J
ergy
(4) -144 J
221. 1 kg of a gas does 20 kJ of work and rer
225. For
inter
on :-
- MODULE_03\01-THERMAL PHYSICS\02- EXERCISE.P65
340
(1) 2
(3) 1
10 KJ of heat when it is eymanded betwee
between two
2​

Answer 1

Answer:

find it yourself

Explanation:

distribute the questions in differrnt sections